2nd version of search in sorted with less code

chapter10/10.03 - Search In Rotated Array/searchInRotatedArrayV2.js

@@ -0,0 +1,62 @@
+/**
+Time O(log n) & Space O(1)
+ * @params: { number[] }
+ * @params: { number }
+ * @results: { number }
+
+ First Binary Search:
+  find out where the array was shifted 
+  perform a binary search on the left and right shifted arrays
+
+ Second Binary Search:
+  See if we can find the element in this subarray
+  if not return -1
+**/
+
+const searchSorted = function (arr, val) {
+  let left = 0;
+  let right = arr.length;
+
+  const binarySearch = function (l, r) {
+    while (l < r) {
+      const m = Math.floor(Math.abs((l + r) / 2));
+
+      if (arr[m] === val) {
+        return m;
+      } else if (arr[m] > val) {
+        r = m;
+      } else {
+        l = m + 1;
+      }
+    }
+    return -1;
+  };
+
+  while (left < right) {
+    const mid = Math.floor(Math.abs((left + right) / 2));
+
+    if (arr[mid] > arr[mid + 1]) {
+      return binarySearch(0, mid + 1) === -1
+        ? binarySearch(mid + 1, arr.length)
+        : binarySearch(0, mid + 1);
+    } else if (arr[mid] < arr[0] && arr[mid] < arr[arr.length - 1]) {
+      right = mid - 1;
+    } else {
+      left = mid + 1;
+    }
+  }
+
+  return -1;
+};
+
+//  indexes =  0,  1,  2,  3,  4, 5, 6, 7, 8, 9, 10, 11
+const arr1 = [15, 16, 19, 20, 25, 1, 3, 4, 5, 7, 10, 14];
+
+console.log(searchSorted(arr1, 5), 8);
+console.log(searchSorted(arr1, 15), 0);
+console.log(searchSorted(arr1, 14), 11);
+
+console.log(searchSorted(arr1, 25), 4);
+console.log(searchSorted(arr1, 1), 5);
+console.log(searchSorted(arr1, 22), -1);
+